In the series L - C - R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E = 500 2 sin ω t , then the peak volt

Question

In the series L - C - R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E = 500 2 sin ω t , then the peak voltage across the capacitor is .

TestHub · Accepted Answer

. V R 2 + ( V L - V C ) 2 = E r m s 2 V L – V C 2 = 500 2 – 400 2 V L – V C = ( 500 ) 2 - ( 400 ) 2 = 300 V C = V L – 30 0 = 700 – 300 = 400 ∴ V C peak = 2 V c = 2 × 4 0 0 volts

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