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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

PhysicsEasynumerical

In the circuit shown, current measured by ammeter is $x$ ampere. Find $x$ .

Answer:

3.00

Solution:

Let current = $x$ ampere
$V_{2} + V_{3} = 40 V$ ( $L$ & $C$ out of phase)
Voltage across $10 Ω = 10 x$

Using phase addition of voltage,
$(10 x)^{2} + (40)^{2} = (50)^{2}$
$\Rightarrow x = 3$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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