The current through the solenoid is changing in such way that flux through it is given by $ϕ = ε t$ . The solenoid is surrounded by a loop having resistance $R_{1}$ and $R_{2}$ as shown. Then the reading of the two voltmeters $V_{1}$ and $V_{2}$ differ by :

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i = 2 ε 1 + 2 ε 2 R 1 + R 2 = ε R 1 + R 2 Where ε = d ϕ dt is the net emf in the circuit ∴ V 1 - V 2 = ε 1 - iR 1 - ε 1 - iR 2 = ε R 2 - R 1 R 1 + R 2

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