A capacitor of capacitance 500 μ F is charged completely using a de supply of 100 V . It is now connected to an inductor of inductance 50 mH to form an LC circuit. The maximum current in LC circuit wi

Question

A capacitor of capacitance 500 μ F is charged completely using a de supply of 100 V . It is now connected to an inductor of inductance 50 mH to form an LC circuit. The maximum current in LC circuit will be _____ A .

TestHub · Accepted Answer

Energy stored in capacitor E = 2 1 ​ C V 2 = 2 1 ​ 500 × 1 0 − 6 × 1 0 4 ⇒ E = 2 5 ​ J Current will be maximum when whole energy of capacitor becomes energy of inductor. ⇒ 2 1 ​ L I 2 = 2 5 ​ ⇒ I = L 5 ​ ​ = 50 × 1 0 − 3 5 ​ ​ = 10 A

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