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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACTransformerEasy2 minPYQ_2020

PhysicsEasysingle choice

In a transformer, the number of turns in the primary coil is $140$ and that in the secondary coil is $280$ . If the current in the primary coil is $4 A$ , then that in the secondary coil is

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Answer:

Solution:

$I_{2} N_{2} = I_{1} N_{1}$

$∴$ $I_{2} = \frac{I_{1} N_{1}}{N_{2}} = \frac{4 \times 140}{280} = 2 A.$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Transformer

⏱ 2mℹ️ Source: PYQ_2020

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