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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsMedium3 minQB

PhysicsMediuminteger

An AC circuit is shown in the figure. If $V = 1002 sin (100 π t)$ , what is the average power dissipated in the circuit (in Watt)?

Answer:

120

Solution:

$P_{a v} = \frac{V _{0} i _{0} c o s ϕ}{2}$
$V_{0} = 1002$
$Z = R^{2} + X_{L}^{2} = 3 0^{2} + 4 0^{2} = 50$
$i_{0} = \frac{V _{0}}{Z} = \frac{100 2}{50}$
$cos ϕ = \frac{R}{Z} = \frac{30}{50} = \frac{3}{5}$
$P_{a v} = \frac{100 2}{2} \times \frac{100 2}{50} \times \frac{3}{5} = 120$ W

Subject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 3mℹ️ Source: QB

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