Physics - EMI/AC Question with Solution | TestHub

Let$\text{I}={\text{I}}_{0}sin\omega \text{t}$

where${\text{I}}_0=10\text{, }\omega =100$

then$\epsilon =\text{M}\frac{\text{dI}}{\text{dt}}$

$=\text{M}\frac{\text{d}}{\text{dt}}{\text{I}}_{0}sin\omega \text{t}$

$=\text{M}{I}_0\omega cos\omega \text{t}$

$\therefore {\epsilon }_{\text{max}}=\text{M}{I}_0\omega$

$5\pi =\text{M}\times 10\times 100\pi$

M = 5 mH