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PhysicsEMI/ACSeries AC CircuitsMedium2 minPYQ_2021
PhysicsMediumnumerical

In anLCRseries circuit, an inductor30 mHand a resistor1 Ωare connected to anACsource of angular frequency300 rad s-1.The value of capacitance for which the current leads the voltage by45°is1x×10-3 F. Then the value ofxis

Answer:
3.00
Solution:

tanϕ=xC-xLR
tan45=xC-xLR
xC-xL=R
1ωC-ωL=R
1ωC-300×0.03=1
1ωC=10
C=110ω=110×300
C=13×10-3
X=3

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits
2mℹ️ Source: PYQ_2021

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