Physics - EMI/AC Question with Solution | TestHub

Force on$SR$and$PQ$are equal but opposite so their net will be zero.

Force between two parallel conductors carrying currents$I_1 \mathrm{a}\mathrm{n}\mathrm{d}\mathrm{ } I_2$

$F=\frac{{\mathrm{\mu }}_0}{2\mathrm{\pi }}\frac{I_1{I}_{2}l}{r}$

Where$r=$distance between two parallel conductors

$F_{PS}=\frac{{10}^{-7}\times 2\times 20\times 20\times 15\times {10}^{-2}}{2\times {10}^{-2}}$

$=6\times {10}^{-4} \mathrm{N}$

$F_{QR}=\frac{{10}^{-7}\times 2\times 20\times 20\times 15\times {10}^{-2}}{12\times {10}^{-2}}$

$=1\times {10}^{-4} \mathrm{N}$

$F_{\mathrm{n}\mathrm{e}\mathrm{t}}=F_{PS}-F_{QR}$

$$\begin{gathered} =6\times {10}^{-4}-1\times {10}^{-4}=5\times {10}^{-4} \mathrm{N} \\ =500 \mathrm{\mu N} \end{gathered}$$