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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACLC oscillationEasy2 minPYQ_2020

PhysicsEasysingle choice

The natural frequency of an $L - C$ circuit is $125000 cycles / s$ . When a dielectric medium of dielectric constant $K$ is introduced between the plates of the capacitor, the frequency decreases by $25 kHz$ . The value of $K$ is

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Answer:

Solution:

$f = \frac{1}{2 π \sqrt{L C}}$

When a dielectric is introduced the capacitance becomes

$C^{'} = K C$

$\Rightarrow \frac{f^{'}}{f} = \sqrt{\frac{C}{C^{'}}}$

$\frac{125000 - 25000}{125000} = \sqrt{\frac{C}{KC}}$

$\frac{100}{125} = \frac{1}{\sqrt{K}}$

$K = {(\frac{125}{100})}^{2} = 1.56$

Subject:PhysicsTopic:EMI/ACSubtopic:LC oscillation

⏱ 2mℹ️ Source: PYQ_2020

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