Physics - EMI/AC Question with Solution | TestHub

Current through an LCR circuit is maximum when impedance is minimum. Now impedance $Z=\sqrt{R^2+{\left(\omega L-\frac{1}{\omega C}\right)}^2}$ is minimum at resonance frequency when $\omega \mathrm{L}=\frac{1}{\omega \mathrm{C}}$ and $\mathrm{Z}=\mathrm{R}=$ minium i.e., inductive reactance $(\omega \mathrm{L})$ is equal to capacitive reactance $(1/\omega C)$