The current in an L C R circuit is given by I = 20 sin ⁡ 100 π t + π 3 A . The voltage across the inductance L of 0 .1 H at t = 0 will be

V = 20 × 100 π × 0.1 sin ⁡ 100 π t + 5 π 6 V = 200 π sin ⁡ 5 π 6 V = 314 V

Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

PhysicsEasysingle choice

The current in an $L C R$ circuit is given by $I = 20 \sin (100 π t + \frac{π}{3}) A .$ The voltage across the inductance $L$ of $0 .1 H$ at $t = 0$ will be

Options:

Answer:

Solution:

$V = (20 \times 100 π \times 0.1) \sin (100 π t + \frac{5 π}{6})$

$V = 200 π \sin \frac{5 π}{6}$

$V = 314 V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...