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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACParallel AC circuitsHard2 minQB

PhysicsHardsingle choice

For the given figures, choose the correct options:

Options:

Answer:

Solution:

For the circuit(a), $Z = R = 40Ω$ . Hence,

$I_{r m s} = \frac{220}{40} = 5.5 A$

$X_{L} = 2 π f L = 2 π \times 50 \times 50 \times 1 0^{- 3} = 15.7Ω$ and $X_{C} = \frac{1}{2 π f C} = \frac{1}{2 π \times 50 \times 0.5 \times 1 0 ^{- 6}} = 6369Ω$

For the circuit(b), $Z = R^{2} + (X_{L} - X_{C})^{2} > 40Ω$ as

$X_{L}$ is not equal to $X_{C}$ . So rms current in (b) can never be larger than (a)

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Parallel AC circuits

⏱ 2mℹ️ Source: QB

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