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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2020

PhysicsEasysingle choice

An E.M.F of $5 V$ is produced in an inductor, when the current changes at a steady rate from $3 A$ to $2 A$ in $1$ millisecond. The value of self-inductance is

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Answer:

Solution:

Magnitude of self inductance is

$L = \frac{e}{\frac{d i}{d t}}$

$L = \frac{5}{\frac{(3 - 2)}{1 0^{- 3}}} = 5 \times 1 0^{- 3}$

$L = 5 m H$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2020

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