Physics - EMI/AC Question with Solution | TestHub

In series$LCR$circuit, the source voltage

$V=\sqrt{V_R^2+{\left(V_L-V_C\right)}^2}$

Here,$V_R=60 \mathrm{V} \Rightarrow V_L=40 V$

$V_C=120 V$

$V=\sqrt{{\left(60\right)}^2+{\left(40-120\right)}^2}$

$=\sqrt{{\left(60\right)}^2+{\left(-80\right)}^2}=\sqrt{3600+6400}$

$=\sqrt{10000}=100 V$