The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with the primary coil is given by ϕ = ϕ v + 4 t , where ϕ is in webers, t is time

Question

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with the primary coil is given by ϕ = ϕ v ​ + 4 t , where ϕ is in webers, t is time in seconds and ϕ v ​ is a constant, the output voltage across the output voltage across the secondary coil is:NEET 2007

TestHub · Accepted Answer

The magnetic flux linked with the primary coil is given by ϕ = ϕ 0 ​ + 4 t So, voltage across primary ​ V p ​ = d t d ϕ ​ = d t d ​ ( ϕ 0 ​ + 4 t ) = 4 volt (as ϕ 0 ​ = constant ) ​ Also, we have N p ​ = 50 and N s ​ = 1500 From relation, ​ V p ​ V s ​ ​ = N p ​ N s ​ ​ or V s ​ = V p ​ N p ​ N s ​ ​ = 4 ( 50 1500 ​ ) = 120 V ​

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