Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

PhysicsEasysingle choice

A $40 μF$ capacitor is connected to a $200 V$ , $50 Hz$ AC supply. The rms value of the current in the circuit is, nearly:NEET 2020 (Phase 1)

Answer:

Solution:

Current flowing through the capacitor is given by, $I_{rms} = \frac{V}{X_{C}} = \frac{V}{1 / C ω} = V C ω$

$\Rightarrow I_{rms} = 200 \times 40 \times 10^{- 6} \times 2 π \times 50$

$\Rightarrow I_{rms} = 2.5 A$

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

Loading discussions...