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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

PhysicsEasysingle choice

An AC voltage source of variable angular frequency $ω$ and fixed amplitude $V_{0}$ is connected in series with a capacitance $C$ and an electric bulb of resistance $R$ (inductance zero). When $ω$ is increased

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Answer:

Solution:

$Z = \sqrt{R^{2} + X_{C}^{2}} I_{r m s} = \frac{V_{r m s}}{Z} P = I_{r m s}^{2} R$
Where $X_{C} = \frac{1}{ω C}$

As $ω$ is increased, $X_{C}$ will decrease or $Z$ will decrease $.$ Hence $I_{r m s} o r P$ will increase $.$ Therefore, bulb glows brighter.

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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