Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACFaraday law/Lenz lawMedium2 minAllen Review Test 24-05-2026 Phase I(A) Paper-2

PhysicsMediuminteger

The square loop has sides of length 2cm. A magnetic field points out of the page and its magnitude is given by $B = (4 t^{2}) T$ . Emf induced in loop is given by x mV at $t = 2.5 s$ . Find the value of x .

Answer:

Solution:

Flux through the loop: $ϕ = B A = (4 t^{2}) (0.02)^{2}$

Induced emf: $ε = A \frac{d B}{d t} = (0.02)^{2} \times 8 t = 3.2 t mV$

At t = 2.5 s: $ε = 3.2 \times 2.5 = 8 mV$

So x = 8. Answer: 8

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: Allen Review Test 24-05-2026 Phase I(A) Paper-2

Doubts & Discussion

Loading discussions...