Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACTransformerEasy2 minPYQ_2019

PhysicsEasysingle choice

In a transformer number of turns in primary circuit is 500 and in secondary circuit number of turns is 10 . The load resistance is $10Ω$ and voltage of secondary coil is $50 V$ . Then find the current in primary circuit.

Options:

Answer:

Solution:

Given, $N_{1} = 500, N_{2} = 10, R_{L} = 10Ω$ $V_{2} = 50 V$ Current in the secondary circuit is $i_{2} = \frac{V _{2}}{R _{L}} = \frac{50}{10} = 5 A \frac{i _{1}}{i _{2}} = \frac{N _{2}}{N _{1}} \Rightarrow \frac{i _{1}}{5} = \frac{10}{500} \Rightarrow i_{1} = 0.1 A$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Transformer

⏱ 2mℹ️ Source: PYQ_2019

Doubts & Discussion

Loading discussions...