Physics - EMI/AC Question with Solution | TestHub

As switch $S_1$ is closed and switch $S_2$ is kept open. Now, capacitor is charging through a resistor $R$. Charge on a capacitor at any time $t$ is $q=q_0\left(1-e^{-t/\tau }\right)=CV\left(1-e^{-t/\tau }\right)$
$\begin{array}{rl}& \text{ At }t=\frac{\tau }{2},q=CV\left(1-e^{-\tau /2\tau }\right)=CV\left(1-e^{-1/2}\right)\\ & \text{ At }t=\tau ,q=CV\left(1-e^{-\tau /\tau }\right)=CV\left(1-e^{-1}\right)\\ & \text{ At }t=2\tau ,q=CV\left(1-e^{-2\tau /\tau }\right)=CV\left(1-e^{-2}\right)\end{array}$