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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACAC current and voltageMedium2 minPYQ_2016

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The equation of $AC$ voltage is $E = 220 sin$ $(ω t + π /6)$ and the A.C. current is $I = 10 sin$ $(ω t + π /6)$ . The average power dissipated is

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Solution:

We know that, $Z = \frac{E _{0}}{I _{0}}$ Given, $E_{0} = 220 V$ and $I_{0} = 10 A$ $so Z = \frac{220}{10} = 22 ohm ϕ p_{a} = [\frac{π}{6} - (- \frac{π}{6})] = \frac{π}{3} = \frac{E _{0}}{2} \times \frac{I _{0}}{2} \times cos ϕ = \frac{220}{2} \times \frac{10}{2} \times cos \frac{π}{3} = 550 W$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage

⏱ 2mℹ️ Source: PYQ_2016

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