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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACQuality and Power factorEasy2 minPYQ_2020

PhysicsEasysingle choice

The power factor of the following circuit will be

Options:

Answer:

Solution:

$Z = \sqrt{R^{2} + (X_{L} - X_{c})^{2}}$
$\Rightarrow Z = \sqrt{(40 + 40)^{2} + (100 - 40)^{2}} = 100 Ω$
$\Rightarrow \cos ϕ = \frac{R}{Z} = \frac{80}{100} = 0.8$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Quality and Power factor

⏱ 2mℹ️ Source: PYQ_2020

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