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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2011

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A coil has resistance $30Ω$ and inductive reactance $20Ω$ at $50 Hz$ frequency. If an $AC$ source of $200 V, 100 Hz$ , is connected across the coil, the current in the coil will beNEET 2011 (Mains)

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Solution:

If $ω = 50 \times 2 π$ then $ω L = 20Ω$ Similarly $ω^{'} = 100 \times 2 π$ then $ω^{'} L = 40Ω$ $i = \frac{200}{Z} = \frac{200}{R ^{2} + ( ω ^{'} L ) ^{2}} = \frac{200}{( 30 ) ^{2} + ( 40 ) ^{2}} = 4 A$

Stream:NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2011

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