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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsMedium2 minPYQ_2005

PhysicsMediumsingle choice

A $50 Hz$ a.c. source of 20 volts is connected across $R$ and $C$ as shown in figure. The voltage across $R$ is 12 volt. The voltage across $C$ is

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Solution:

$: v = 50 Hz, V = 20 V, V_{R} = 12 V$ In case of $RC$ circuit, $V = V_{R}^{2} + V_{C}^{2}$ $\Rightarrow (20)^{2} = (12)^{2} + (V_{C})^{2} \Rightarrow (V_{C})^{2} = 400 - 144 = 256 \Rightarrow V_{C} = 16 V$

Stream:AIIMSSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2005

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