With the decrease of current in the primary coil from 2 amperes to zero value in 0.01 s the emf generated in the secondary coil is 1000 volts. The mutual inductance of the two coils is

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Induced emf ε = d t − M d I P ​ ​ Where M is the mutual inductance of two coils and d t d I P ​ ​ is the rate of change of current in the primary. ​ ∴ 1000 V = 0.01 s − M ( 0 A − 2 A ) ​ or M = ( 2 A ) ( 1000 V ) ( 0.01 s ) ​ = 5 H . ​

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