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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACFaraday law/Lenz lawMedium2 minQB

PhysicsMediumnumerical

The square loop has sides of length 2cm. A magnetic field points out of the page and its magnitude is given by $B = (4 t^{2} y) T$ . Emf induced in loop is given by $\frac{x}{10} μ V$ at $t = 2.5 s$ . Find the value of x .

Answer:

800.00

Solution:

$B = (4 t^{2} y) T$ , $d A = B \cdot 2 d y \times 1 0^{- 2}$

$ϕ = \int_{0}^{2 cm} 4 t^{2} y \times 2 \times 1 0^{- 2} d y = 16 t^{2} \times 1 0^{- 6}$

$e = \frac{d ϕ}{d t} = 32 t \times 1 0^{- 6} = 32 \times 2.5 μ V$ at $t = 2.5 s$

$\frac{x}{10} = \frac{32 \times 25}{10} \Rightarrow x = 800$

Answer: 800.00

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: QB

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