Physics - Electrostatics Question with Solution | TestHub

Work done by electrostatic field is $\frac{{\mathrm{kq}}^2}{\mathrm{a}}\left[\frac{1-2\sqrt{2}}{\sqrt{2}}\right]\mathrm{J}$

Work done by external agent is $\frac{{\mathrm{kq}}^2}{\mathrm{a}}\left[\frac{1-2\sqrt{2}}{\sqrt{2}}\right]\mathrm{J}$

Total potential energy of the system after the charge is placed at the corner is $\frac{{\mathrm{kq}}^2}{\mathrm{a}}[\sqrt{2}-4]$

For the system thus achieved centre of square will be a point of equilibrium.