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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2023

PhysicsMediumsingle choice

If a conducting sphere of radius $R$ is charged. Then the electric field at a distance $r (r > R)$ from the centre of the sphere would be, $(V =$ potential on the surface of the sphere $)$ NEET 2023 (Manipur)

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Solution:

For $r > R$ , Electric field $E = \frac{K q}{r ^{2}} \dots$ and potential at surface of sphere $V = \frac{K q}{R}$ $∴$ From equation (1) $V = \frac{E r ^{2}}{R}$ $\Rightarrow E = \frac{R V}{r ^{2}}$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2023

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