Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minQB

PhysicsMediummultiple choice

A particle is dropped from a height equal to the radius of the earth above the tunnel dug through the earth as shown in the figure.

Answer:

A, C, D

Solution:

Let r is distance from center,

$If r > R F = \frac{GM m}{r ^{2}} (Not SHM) r < R F = \frac{GM m r}{R ^{3}} (SHM)$

⇒ But motion is periodic to find velocity at center, Apply COME,

$\frac{1}{2} m (0^{2}) - \frac{GM m}{2 R} = \frac{1}{2} m v_{C}^{2} - \frac{3}{2} \frac{GM m}{R} v_{C} = \frac{2 GM}{R}$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: QB

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