Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceEasy2 minPYQ_2024

PhysicsEasysingle choice

If two charges $q_{1}$ and $q_{2}$ are separated with distance ' $d$ ' and placed in a medium of dielectric constant $K$ . What will be the equivalent distance between charges in air for the same electrostatic force ?

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Answer:

Solution:

As. $F$ (air)= $F$ (medium) $\Rightarrow \frac{1}{4 π ϵ _{0}} \frac{q _{1} q _{2}}{d _{air}^{2}} = \frac{1}{K} \frac{1}{4 π ϵ _{0}} \frac{q _{1} q _{2}}{d ^{2}} \Rightarrow d_{air} = d K$

Stream:BITSATSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2024

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