Two light rays having the same wavelength λ in vacuum are in phase initially. Then the first ray travels a path l 1 through a medium of refractive index n 1 while the second ray travels a path of

Question

Two light rays having the same wavelength $λ$ in vacuum are in phase initially. Then the first ray travels a path $l_{1}$ through a medium of refractive index $n_{1}$ while the second ray travels a path of length $l_{2}$ through a medium of refractive index $n_{2}$ . The two waves are then combined to observe interference. The phase difference between the two waves is

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Answer:

B

Solution:

Optical path for ray $1 = n_{1} l_{1}$ Optical path for ray $2 = n_{2} l_{2}$ Phase difference, $Δ ϕ = \frac{2 π}{λ} Δ x = \frac{2 π}{λ} (n_{1} l_{1} - n_{2} l_{2})$

TestHub · Accepted Answer

Optical path for ray 1 = n 1 ​ l 1 ​ Optical path for ray 2 = n 2 ​ l 2 ​ Phase difference, Δ ϕ = λ 2 π ​ Δ x = λ 2 π ​ ( n 1 ​ l 1 ​ − n 2 ​ l 2 ​ )

Physics - Electrostatics Question with Solution | TestHub

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