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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A hollow charged metal sphere has radius $r$ . If the potential difference between its surface and a point at distance $3 r$ from the centre is $V$ , then the electric field intensity at distance $3 r$ from the centre is

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Answer:

Solution:

$V_{A} - V_{B} = \frac{kQ}{r} - \frac{kQ}{3 r} = V = \frac{2 kQ}{3 r}$

$E = \frac{k Q}{{(3 r)}^{2}} = \frac{k Q}{9 r^{2}} \Rightarrow E = \frac{V}{6 r}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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