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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsGauss LawHard2 minPDF

PhysicsHardnumerical range

Consider a uniformly charged very long solid non-conducting cylinder of radius R and having volume charge density $ρ = \in_{0}$ . Find electric flux (in SI unit) through a gaussian spherical surface of radius 2R and having one of its diameter along the axis of cylinder and centre on axis of cylinder.

Answer:

3.73

Solution:

$Φ = \frac{Q _{e n c}}{ϵ _{0}}$

Integrate the part of the charged cylinder enclosed by the Gaussian sphere.

$R = (1/ π)^{1/3}$ gives the required flux approximately 3.74 SI units.

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PDF

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