The electric potential V is given as a function of distance × ( metre ) by V = ( 5 x 2 + 10 x − 4 ) volt. Question: Value of electric field at x = 1 m is

V = 5 x 2 + 10 x − 4 E = dx − dV = − ( 10 x + 10 ) At x = 1 m , E = − 20 V / m

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PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2021

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The electric potential $V$ is given as a function of distance $\times ($ metre $)$ by $V = (5 x^{2} + 10 x - 4)$ volt.Question:Value of electric field at $x = 1 m$ is

Options:

Answer:

Solution:

$V = 5 x^{2} + 10 x - 4$ $E = \frac{- dV}{dx} = - (10 x + 10)$ At $x = 1 m, E = - 20 V / m$

Stream:BITSATSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2021

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