A point charge q is placed at a distance 2 r from the centre O of a conducting neutral sphere of radius r . Due to the induced charge on the sphere, the electric potential at point P on the surface of sphere is x volt. Then find the value of x. (If $\frac{kq}{r} = 18$ volt)

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TestHub · Accepted Answer

For a neutral isolated conducting sphere, use the image-charge construction plus the constant potential needed for zero net induced charge.

$V_{s u r f a ce} = \frac{k q}{6 r}$

$\frac{k q}{r} = 18 V \Rightarrow V = 3 V$

$x = 3$

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