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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsdipoleEasy2 minPYQ_2020

PhysicsEasysingle choice

An electric dipole of length $2 cm$ is placed with its axis making an angle of $30 °$ to a uniform electric field $10^{5} N C^{- 1}$ . If it experiences a torque of $10 \sqrt{3} N m$ , then potential energy of dipole is

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Answer:

Solution:

We know that

$τ = pEsin θ$

$\Rightarrow τ = pEsin 30$

$\Rightarrow 10 \sqrt{3} = \frac{pE}{2}$

$\Rightarrow pE = 20 \sqrt{3}$

Potential energy, $U = - pEcos 30 °$

$∴$ Potential energy $U = - 20 \sqrt{3} \times \frac{\sqrt{3}}{2}$

$= - 10 \times 3 = - 30 J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:dipole

⏱ 2mℹ️ Source: PYQ_2020

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