Physics - Electrostatics Question with Solution | TestHub

$\frac{q{q}_1}{4\pi {\epsilon }_0{a}^2}\times \sqrt{2}$

$\frac{q{q}_1}{4\pi {\epsilon }_0\sqrt{2}{a}^2}+\frac{q{q}_1}{8\pi {\epsilon }_0{a}^2}$

$\frac{q{q}_1}{4\pi {\epsilon }_0{a}^2}\left(\sqrt{2}+\frac{1}{2}\right)$

$\frac{q{q}_1}{4\pi {\epsilon }_0{a}^2}\left(\frac{1}{2}-\sqrt{2}\right)$