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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

The magnitude and direction of the electric field at point $P$ can be best represented by

Options:

Answer:

Solution:

${\vec{E}}_{P} = E' c o s 45 ° \hat{i} + E' s i n 45 ° \hat{j}$

$= E' (\frac{\hat{i}}{\sqrt{2}} + \frac{\hat{j}}{\sqrt{2}}) = \frac{k 3 q}{{(\frac{x}{\sqrt{2}})}^{2}} (\frac{\hat{i}}{\sqrt{2}} + \frac{\hat{j}}{\sqrt{2}})$

$= \frac{6 k q}{x^{2}} (\frac{\hat{i}}{\sqrt{2}} + \frac{\hat{j}}{\sqrt{2}}) = \frac{3 \sqrt{2} k q}{x^{2}} (\hat{i} + \hat{j})$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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