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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

A circular ring of radius $R$ and uniform linear charge density $+ λ$ $C / m$ are kept in $x - y$ plane with its centre at the origin. The electric field at a point $(0,0, \frac{R}{\sqrt{2}})$ is

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Answer:

Solution:

$E_{a x i s} = \frac{1}{4 π ε_{0}} \frac{q z}{(R^{2} + z^{2})^{\frac{3}{2}}}$ , at $z = \frac{R}{\sqrt{2}}$

$\Rightarrow E_{a x i s} = \frac{2}{3 \sqrt{3}} \frac{1}{4 π ε_{0}} \frac{q}{R^{2}}$

$\Rightarrow E_{a x i s} = \frac{2}{3 \sqrt{3}} . \frac{1}{4 π ε_{0}} . \frac{λ . 2 π R}{R^{2}}$

$\Rightarrow E_{a x i s} = \frac{λ}{3 \sqrt{3} ε_{0} R}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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