Physics - Elecrostatics Question with Solution | TestHub

PhysicsElecrostaticsElectric Field & ForceMedium2 minPYQ_2021

PhysicsMediumsingle choice

What will be the magnitude of the electric field at point $O$ as shown in the figure? Each side of the figure is $l$ and perpendicular to the other?

Answer:

Solution:

$E_{1} = \frac{k q}{l^{2}} = E_{2}$

$E_{3} = \frac{k q}{(\sqrt{2} ℓ l} = \frac{k q}{2 l^{2}}$

$E = \frac{\sqrt{2} k q}{l^{2}} - \frac{k q}{2 l^{2}} = \frac{k q}{2 l^{2}} (2 \sqrt{2} - 1)$

Stream:JEESubject:PhysicsTopic:ElecrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2021

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