Physics - Electrostatics Question with Solution | TestHub

Time to cross$0.10\text{m},$$t=\frac{0.10}{4\times {10}^7}\mathrm{s}$

Distance deviated in this time due to electric field$=\frac{1}{2}\left(\frac{eE}{m}\right).t^2$

$=\frac{1}{2}\times \frac{1.6\times {10}^{-19}\times 3200}{9.1\times {10}^{-31}}$$\times {\left(\frac{0.1}{4\times {10}^7}\right)}^2\text{m}$

$=01.76\mathrm{mm}$