Two parallel large thin metal sheets have equal surface charge densities ( σ = 26.4 × 1 0 − 12 C / m 2 ) of opposite signs. The electric field between these sheets is

Electric field between the sheets is E = ε 0 σ = 8.85 × 1 0 − 12 26.4 × 1 0 − 12 ≈ 3 N / C .

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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceEasy2 minPYQ_2006

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Two parallel large thin metal sheets have equal surface charge densities $(σ = 26.4 \times 1 0^{- 12} C / m^{2})$ of opposite signs. The electric field between these sheets is

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Electric field between the sheets is $E = \frac{σ}{ε _{0}} = \frac{26.4 \times 1 0 ^{- 12}}{8.85 \times 1 0 ^{- 12}} \approx 3 N / C .$

Stream:AIIMSSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2006

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