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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A body of mass $1 g$ and carrying a charge $1 0^{- 8} C$ passes from two points $P$ and $Q$ . $P$ and $Q$ are at electric potentials $600 V$ and $0 V$ respectively. The velocity of the body at $Q$ is $20 c m s^{- 1}$ . Its velocity in $m s^{- 1}$ at $P$ is

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Answer:

Solution:

Potentials, $V_{P} = 600 V$ $V_{Q} = 0 V$

Conserving mechanical energy,

$K_{P} + U_{P} = K_{Q} + U_{Q}$

$\frac{1}{2} m v_{P}^{2} + q v_{R} = \frac{1}{2} m v_{Q}^{2} + q v_{Q}$

$\frac{1}{2} m (v_{P}^{2} - v_{Q}^{2}) = q (V_{Q} - V_{P})$

$\frac{1}{2} (1 0^{- 3}) [v_{P}^{2} - {(0.2)}^{2}] = 1 0^{- 8} (0 - 600)$

$v_{P}^{2} - 0.04 = - 12 \times 1 0^{- 3}$

$v_{P}^{2} = 0.04 - 0.012$

$v_{P} = \sqrt{0.028} m s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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