In finding the electric field using Gauss law the formula E → = q e n c ε 0 A is applicable. In the formula ε 0 is permittivity of free space, A is the area of Gaussian surface and q e n c is charge e

Question

In finding the electric field using Gauss law the formula E → = q e n c ε 0 A is applicable. In the formula ε 0 is permittivity of free space, A is the area of Gaussian surface and q e n c is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?

TestHub · Accepted Answer

According to Gauss law of electrostatics, the electric flux through an enclosed surface is given by $ϕ_{E} = \frac{q_{enc}}{ε_{0}}$

From the formula of electric flux, $ϕ = \vec{E} \cdot d \vec{s}$

Also, the relation between electric field and electric potential is given by $V = \vec{E} \cdot d \vec{r}$

So, the formula $|\vec{E}| = \frac{q_{enc}}{ε_{0} |A|}$ is only applicable when the Gaussian surface is an equipotential surface and $|\vec{E}|$ is constant on the surface.

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