An electric field of 1000 V / m is applied to an electric dipole at angle of 4 5 ∘ . The value of electric dipole moment is 1 0 − 29 C ⋅ m . What is the potential energy of the electric dipole?

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PhysicsElectrostaticsdipoleEasy2 minPYQ_2019

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An electric field of $1000 V / m$ is applied to an electric dipole at angle of $4 5^{\circ}$ . The value of electric dipole moment is $1 0^{- 29} C \cdot m .$ What is the potential energy of the electric dipole?

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Solution:

Potential energy of a dipole is given by $U = - P E$ $= - PE cos θ$ [Where $θ =$ angle between dipole and perpendicular to the field $= - (1 0^{- 29}) (1 0^{3}) cos 4 5^{\circ}$ $= - 0.707 \times 1 0^{- 26} J = - 7 \times 1 0^{- 27} J$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:dipole

⏱ 2mℹ️ Source: PYQ_2019

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