Start Free Mock LoginAlready registered? Login here

Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two small identical spheres having charges $+ 10 μC$ and $- 90 μC$ attract each other with a force of $F$ newton. If they are kept in contact and then separated by the same distance, the new force between them is -

Options:

Answer:

Solution:

$F = \frac{k (10) (90)}{r^{2}} \dots \dots . . (i)$

charge on each when contact is made

$q_{1}' = q_{2}' = \frac{10 + (- 90)}{2} = - 40 μ C$

$∴$ New force $F' = \frac{k (40) (40)}{r^{2}}$

$∴ \frac{F'}{F} = \frac{40 \times 40}{10 \times 90} = \frac{16}{9}$

$∴ F^{'} = \frac{16}{9} F$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...