A liquid drop having 6 excess electrons is kept stationary under a uniform electric field of 25.5 kVm − 1 . The density of liquid is 1.26 × 1 0 3 kg m − 3 . The radius of the drop is (neglect buoyancy

Question

A liquid drop having 6 excess electrons is kept stationary under a uniform electric field of 25.5 kVm − 1 . The density of liquid is 1.26 × 1 0 3 kg m − 3 . The radius of the drop is (neglect buoyancy).

TestHub · Accepted Answer

F = qE = m g ( q = 6 e = 6 × 1.6 × 1 0 − 19 ) Density ( d ) = volume mass ​ = 3 4 ​ π r 3 m ​ or r 3 = 3 4 ​ π d m ​ Putting the value of d and m ( = g qE ​ ) and solving we get r = 7.8 × 1 0 − 7 m

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