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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2019

PhysicsMediumsingle choice

Two point charges A and B, having charges $+ Q$ and $- Q$ respectively, are placed at certain distance apart and force acting between them is $F$ . If $25 %$ charge of $A$ is transferred to $B$ , then the force between the charges becomesNEET 2019 (All India)

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Answer:

Solution:

$F = \frac{K Q^{2}}{r^{2}}$
After transferring $25 %$ of charge, $q_{1} = \frac{3 Q}{4}$ and $q_{2} = - \frac{3 Q}{4}$
$F_{1} = \frac{9}{16} \frac{K Q^{2}}{r^{2}} = \frac{9}{16} F$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2019

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