Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020
PhysicsEasysingle choice

A charged particleqis shot towards another charged particleQ(which is fixed) with a speedv. It approachesQup to the closest distancerand then returns. Ifqwere given a speed2v, the closest distance of approach would be

Options:

Answer:
D
Solution:

From conservation of mechanical energy

12mv2=kqQr

In second case

12m(2v⁡)2=kqQr′

r′=r4

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy
⏱ 2mℹ️ Source: PYQ_2020

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